Your Results | Global Average | |
---|---|---|
Questions | 5 | 5 |
Correct | 0 | 2.98 |
Score | 0% | 60% |
90 lbs. | |
540 lbs. | |
180 lbs. | |
183 lbs. |
The mechanical advantage (MA) of a block and tackle pulley is equal to the number of times the effort force changes direction. An easy way to count how many times the effort force changes direction is to count the number of ropes that support the resistance which, in this problem, is 4. With a MA of 4, a 45 lbs. effort force could lift 45 lbs. x 4 = 180 lbs. resistance.
50 lbs. | |
26.67 lbs. | |
2 lbs. | |
8.89 lbs. |
fAdA = fBdB + fCdC
For this problem, this equation becomes:
25 lbs. x 12 ft. = 30 lbs. x 2 ft. + fC x 9 ft.
300 ft. lbs. = 60 ft. lbs. + fC x 9 ft.
fC = \( \frac{300 ft. lbs. - 60 ft. lbs.}{9 ft.} \) = \( \frac{240 ft. lbs.}{9 ft.} \) = 26.67 lbs.
7% | |
120% | |
15% | |
30% |
0.83 | |
6 | |
1.2 | |
-1 |
The mechanical advantage of a wheel and axle is the input radius divided by the output radius:
MA = \( \frac{r_i}{r_o} \)
In this case, the input radius (where the effort force is being applied) is 6 and the output radius (where the resistance is being applied) is 5 for a mechanical advantage of \( \frac{6}{5} \) = 1.2
0 | |
65 | |
14 | |
87 |