Free ASVAB Practice Tests

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Sample Practice Test Questions

Electronics Information

An inductor __________ changes in the electric current flowing through it.

resists

An inductor is coiled wire that stores electric energy in the form of magnetic energy and resists changes in the electric current flowing through it. If current is increasing, the inductor produces a voltage that slows the increase and, if current is decreasing, the magnetic energy in the coil opposes the decrease to keep the current flowing longer. In contrast to capacitors, inductors allow DC to pass easily but resist the flow of AC.

Automotive Information

Which of the following is not a component in the engine lubrication system?

differential

In engine lubrication, oil remains in the oil pan until the engine is turned on. It then gets sucked up the pickup tube by the oil pump and pressurized. This pressure is moderated by the pressure relief valve and the oil is fed through the oil filter into the engine to lubricate it.

Math Knowledge
y = -2x - 2

The endpoints of this line segment are at (-2, 2) and (2, -6). What is the slope-intercept equation for this line?

y = -2x - 2

The slope-intercept equation for a line is y = mx + b where m is the slope and b is the y-intercept of the line. From the graph, you can see that the y-intercept (the y-value from the point where the line crosses the y-axis) is -2. The slope of this line is the change in y divided by the change in x. The endpoints of this line segment are at (-2, 2) and (2, -6) so the slope becomes:

m = \( \frac{\Delta y}{\Delta x} \) = \( \frac{(-6.0) - (2.0)}{(2) - (-2)} \) = \( \frac{-8}{4} \)
m = -2

Plugging these values into the slope-intercept equation:

y = -2x - 2

Mechanical Comprehension

What's the last gear in a gear train called?

driven gear

A gear train is two or more gears linked together. Gear trains are designed to increase or reduce the speed or torque outpout of a rotating system or change the direction of its output. The first gear in the chain is called the driver and the last gear in the chain the driven gear with the gears between them called idler gears.

Mechanical Comprehension
26.67 lbs. If the green box weighs 30 lbs. and is 8 ft. from the fulcrum, how much force would need to be applied at the blue arrow to balance the lever if the arrow's distance from the fulcrum is 9 ft.?
26.67 lbs.

To balance this lever the torques at the green box and the blue arrow must be equal. Torque is weight x distance from the fulcrum so the equation for equilibrium is:

Rada = Rbdb

where a represents the green box and b the blue arrow, R is resistance (weight/force) and d is the distance from the fulcrum.

Solving for Rb, our missing value, and plugging in our variables yields:

Rb = \( \frac{R_ad_a}{d_b} \) = \( \frac{30 lbs. \times 8 ft.}{9 ft.} \) = \( \frac{240 ft⋅lb}{9 ft.} \) = 26.67 lbs.

Shop Information

When cutting hard metals with a hacksaw you should choose a blade with __________ teeth per inch (TPI).

high

Blades with more and smaller teeth (high TPI) cut harder metals more effectively while blades with fewer and larger teeth (low TPI) cut softer metals more effectively.

Mechanical Comprehension
If input effort is 700 ft⋅lb, what output effort will be produced by a machine with a mechanical advantage of 5?
3500 ft⋅lb
Mechanical advantage is the ratio of output force to input force and tells us by how many times a machine multiplies input effort. So, a machine with a mechanical advantage of 5 will multiply an input effort of 700 ft⋅lb by 5 to produce an output effort of 3500 ft⋅lb.
Word Knowledge
Jade placed the fragile vase out of reach of her rambunctious boys.
frail
Delicate.
Word Knowledge
Implement most nearly means:
execute
To carry out or accomplish.
Math Knowledge

Solve for y:
-6y + 9 = -7 + 7y

1\(\frac{3}{13}\)

To solve this equation, repeatedly do the same thing to both sides of the equation until the variable is isolated on one side of the equal sign and the answer on the other.

-6y + 9 = -7 + 7y
-6y = -7 + 7y - 9
-6y - 7y = -7 - 9
-13y = -16
y = \( \frac{-16}{-13} \)
y = 1\(\frac{3}{13}\)